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Year 10 Interactive Maths - Second Edition


Transpositions Involving Two or More Operations

In general:

To obtain the subject of the formula, we:

  • Clear fractions by multiplying both sides by the lowest common denominator.
  • Add (or subtract) the same number to (from) each side.
  • Multiply (or divide) both sides by the same number.
  • Take the square (or square root) of both sides.
  • If necessary, rearrange the formula so that the subject of the formula appears on the LHS.


Example 42

Transpose the formula v = u + at to make t the subject.

Solution:

Subtract u from both sides, then divide both sides by a and rearrange to find t = (v - u) / a.

Note that we could have obtained t as follows:

Divide both sides by a, then subtract u / a from both sides and rearrange to find t = (v - u) / a.

We notice that there is no unique method to use. However, it is necessary to follow the laws of algebra carefully in isolating the subject.


Example 43

Transpose the formula, A = 2(Pi)r(r + h) to make h the subject.

Solution:
First Method

Divide both sides by 2(Pi)r, subtract r from both sides and rearrange to find h = A / 2(Pi)r - r.

Second Method

Remove the brackets with the Distributive Law, then subtract 2(Pi)(r squared) from both sides, divide both sides by 2(Pi)r and rearrange to find h = (A - 2(Pi)(r squared)) / (A - 2(Pi)r)


Note:

The two methods appear to lead to different results, but they are just different forms of the same result.

By using the Lowest Common Multiple of the denominators from the first result, we see that the first and second result are the same.

This is the same as the result obtained by the second method.


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